0=0.25x^2+2x-10

Solution for 0=0.25x^2+2x-10 equation:

0=0.25x^2+2x-10

We move all terms to the left:

0-(0.25x^2+2x-10)=0

We add all the numbers together, and all the variables

-(0.25x^2+2x-10)=0

We get rid of parentheses

-0.25x^2-2x+10=0

a = -0.25; b = -2; c = +10;
Δ = b2-4ac
Δ = -22-4·(-0.25)·10
Δ = 14
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{14}}{2*-0.25}=\frac{2-\sqrt{14}}{-0.5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{14}}{2*-0.25}=\frac{2+\sqrt{14}}{-0.5}
$